KCET · Physics · Magnetic Properties of Matter
A solenoid has length \( 0.4 \mathrm{~cm} \), radius \( 1 \mathrm{~cm} \) and \( 400 \) turns of wire. If a current of \( 5 \mathrm{~A} \) is passed through this solenoid, what is the magnetic field inside the solenoid?
- A \( 6.28 \times 10^{-4} \mathrm{~T} \)
- B \( 6.28 \times 10^{-3} \mathrm{~T} \)
- C \( 6.28 \times 10^{-7} \mathrm{~T} \)
- D None of the above
Answer & Solution
Correct Answer
(D) None of the above
Step-by-step Solution
Detailed explanation
Given, length of solenoid \(=0.4 \mathrm{~cm}=0.4 \times 10^{-2} \mathrm{~m} ;\) radius \(=1 \mathrm{~cm}=10^{-2} \mathrm{~m} ;\) number of turns \(=400 ;\) current
through solenoid \(=5 \mathrm{~A}\).
Therefore, magnetic field inside solenoid \(=\mu_{0} n I\)
\(=4 \Pi \times 10^{-7} \times \frac{400}{0.4 \times 10^{-2}} \times 5\)
\(=0.628 \mathrm{~T}\)
through solenoid \(=5 \mathrm{~A}\).
Therefore, magnetic field inside solenoid \(=\mu_{0} n I\)
\(=4 \Pi \times 10^{-7} \times \frac{400}{0.4 \times 10^{-2}} \times 5\)
\(=0.628 \mathrm{~T}\)
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