KCET · Chemistry · Thermodynamics (C)
From the diagram
\(\Delta_r H\) for the reaction, \(C \rightarrow A\) is
- A \(+35 \mathrm{~J}\)
- B \(-15 \mathrm{~J}\)
- C \(-35 \mathrm{~J}\)
- D \(+15 \mathrm{~J}\)
Answer & Solution
Correct Answer
(C) \(-35 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
\(\Delta_r H\) for \(C \rightarrow A\) is given by
\(\underset{(A \rightarrow C)}{\Delta H}=\underset{(A \rightarrow B)}{\Delta H_1}+\underset{(B \rightarrow C)}{\Delta H_2}\)
\(\underset{(A \rightarrow C)}{\Delta H_C}=10+25=35 \mathrm{~J}\)
\(\underset{C \rightarrow A}{\Delta H}=-\underset{A \rightarrow C}{\Delta H}\)
\(\underset{c \rightarrow A}{\Delta H_1}=-35 \mathrm{~J}\)
\(\underset{(A \rightarrow C)}{\Delta H}=\underset{(A \rightarrow B)}{\Delta H_1}+\underset{(B \rightarrow C)}{\Delta H_2}\)
\(\underset{(A \rightarrow C)}{\Delta H_C}=10+25=35 \mathrm{~J}\)
\(\underset{C \rightarrow A}{\Delta H}=-\underset{A \rightarrow C}{\Delta H}\)
\(\underset{c \rightarrow A}{\Delta H_1}=-35 \mathrm{~J}\)
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