KCET · Chemistry · p Block Elements (Group 15, 16, 17 & 18)
\( 0.1 \) mole of \( X e F_{6} \) is treated with \( 1.8 \mathrm{~g} \) of water. The product obtained is
- A \( \mathrm{XeOF}_{4} \)
- B \( \mathrm{Xe}+\mathrm{XeO}_{3} \)
- C \( \mathrm{XeO}_{3} \)
- D \( \mathrm{XeO}_{2} \mathrm{~F}_{2} \)
Answer & Solution
Correct Answer
(A) \( \mathrm{XeOF}_{4} \)
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