KCET · BIOLOGY · STD 12 - 6. Evolution
The allele frequency of 'A' and 'a' in a population are 0.6 and 0.4 respectively. the expected frequency of heterozygous individuals is
- A 48%
- B 36%
- C 16%
- D 24%
Answer & Solution
Correct Answer
(A) 48%
Step-by-step Solution
Detailed explanation
(A) 48%,
In a population, autosomal dominant -recessive inheritance can be expressed by Hardy - Weinberg. The simple algebraic expression is:
\(p^2+2 p q+q^2=1\)
where, p is the frequency of A = 0.6
q is the frequency of a = 0.4
2pq is the frequency of Aa (heterozygous individuals)
= 2 x 0.6 x 0.4 = 48
Thus, the expected frequency of heterozygous individuals
= 48%
In a population, autosomal dominant -recessive inheritance can be expressed by Hardy - Weinberg. The simple algebraic expression is:
\(p^2+2 p q+q^2=1\)
where, p is the frequency of A = 0.6
q is the frequency of a = 0.4
2pq is the frequency of Aa (heterozygous individuals)
= 2 x 0.6 x 0.4 = 48
Thus, the expected frequency of heterozygous individuals
= 48%
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