KCET · Chemistry · General Principles and Processes of Isolation of Metals
For the formation of which compound in Ellingham diagram \(\Delta G^{\circ}\) becomes more and more negative with increase in temperature?
- A \(\mathrm{CO}\)
- B \(\mathrm{FeO}\)
- C Zno
- D \(\mathrm{Cu}_2 \mathrm{O}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{CO}\)
Step-by-step Solution
Detailed explanation
For formation of carbon monoxide ( \(\mathrm{CO}\) ), the
Ellingham diagram shows that the \(\Delta G^{\circ}\) becomes negative with an increase in temperature. It indicates that the formation of \(\mathrm{CO}\) from carbon
(C) and oxygen \(\left(\mathrm{O}_2\right)\) becomes more favourable at higher temperatures.
Ellingham diagram shows that the \(\Delta G^{\circ}\) becomes negative with an increase in temperature. It indicates that the formation of \(\mathrm{CO}\) from carbon
(C) and oxygen \(\left(\mathrm{O}_2\right)\) becomes more favourable at higher temperatures.
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