KCET · Chemistry · Redox Reactions
For an ideal binary liquid mixture
- A \( \Delta \mathrm{H}_{(\text {mix })}=0 ; \Delta \mathrm{S}_{(\text {mix })} < 0 \)
- B \( \Delta \mathrm{S}_{(\mathrm{mix})}>0 ; \Delta \mathrm{G}_{(\mathrm{mix})} < 0 \)
- C \( \Delta S_{(\mathrm{mix})}=0 ; \Delta G_{(\mathrm{mix})}=0 \)
- D \( \Delta \mathrm{V}_{(\text {mix })}=0 ; \Delta \mathrm{G}_{(\text {mix })}>0 \)
Answer & Solution
Correct Answer
(B) \( \Delta \mathrm{S}_{(\mathrm{mix})}>0 ; \Delta \mathrm{G}_{(\mathrm{mix})} < 0 \)
Step-by-step Solution
Detailed explanation
For an ideal binary liquid mixture \(\Delta S_{\operatorname{mix}}>0\) and \(\Delta G_{\operatorname{mix}} < 0\)
For ideal solution;
\(\Delta H_{\operatorname{mix}}=0\) and \(\Delta V_{\operatorname{mix}}=0\)
\(\Delta G=\Delta \mathrm{H}-\mathrm{T} \Delta S\)
\(\Delta G\) should be \(-\) ve for reaction to be spontaneous, that is, \(\Delta G < 0\).
When \(\Delta G < 0\), then \(\Delta S\) should have value greater than zero
For ideal solution;
\(\Delta H_{\operatorname{mix}}=0\) and \(\Delta V_{\operatorname{mix}}=0\)
\(\Delta G=\Delta \mathrm{H}-\mathrm{T} \Delta S\)
\(\Delta G\) should be \(-\) ve for reaction to be spontaneous, that is, \(\Delta G < 0\).
When \(\Delta G < 0\), then \(\Delta S\) should have value greater than zero
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