KCET · Chemistry · Classification of Elements and Periodicity in Properties
An aromatic compound ' \( \mathrm{A} \) ' \( \left(\mathrm{C}_{7} \mathrm{H}_{9} \mathrm{~N}\right) \) on reacting with \( \mathrm{NaNO}_{2} / \mathrm{HCl} \) at \( 0^{\circ} \mathrm{C} \) forms benzyl
alcohol and nitrogen gas. The number of isomers possible for the compound ' \( A \) ' is
- A \( 7 \)
- B \( 06 \)
- C \( 55 \)
- D \( 13 \)
Answer & Solution
Correct Answer
(C) \( 55 \)
Step-by-step Solution
Detailed explanation
The reaction involved is
No. of isomeric forms of \( C_{7} H_{9} N \)
o-Toluidine
\( m \)-Toluidine
\( \mathrm{CH}_{3} \)
\( p \)-Toluidine
\( \mathrm{CH}_{2} \mathrm{NH}_{2} \)
No. of isomeric forms of \( C_{7} H_{9} N \)
o-Toluidine
\( m \)-Toluidine
\( \mathrm{CH}_{3} \)
\( p \)-Toluidine
\( \mathrm{CH}_{2} \mathrm{NH}_{2} \)
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