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The co-ordination number and the oxidation state of the element ' \( M \) ' in the complex
\( \left[\mathrm{M}(\mathrm{en})_{2}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)\right] \mathrm{NO}_{2} \) [where (en) is ethan-1,2 - diamine] are respectively
- A \( 6 \) and \( 3 \)
- B \( 6 \) and \( 2 \)
- C \( 4 \) and \( 2 \)
- D \( 4 \) and \( 3 \)
Answer & Solution
Correct Answer
(A) \( 6 \) and \( 3 \)
Step-by-step Solution
Detailed explanation
Oxidation number of \( M \) metal ion in the given complex,
\( x+(2 \times 0)+1 \times(-2)=1 \)
\( x=+3 \)
Since, metal is linked with \( 6 \) donor sites.
Therefore, coordination no. is \( 6 \)
The coordination number is six and the oxidation state of theelement \( \mathrm{M} \) in the complex \( \left[\mathrm{M}(\mathrm{en})_{2}\left(\mathrm{C}_{2} \mathrm{O}_{2}\right)\right] \mathrm{N} \mathrm{O}_{2} \) is \( +3 \)
\( x+(2 \times 0)+1 \times(-2)=1 \)
\( x=+3 \)
Since, metal is linked with \( 6 \) donor sites.
Therefore, coordination no. is \( 6 \)
The coordination number is six and the oxidation state of theelement \( \mathrm{M} \) in the complex \( \left[\mathrm{M}(\mathrm{en})_{2}\left(\mathrm{C}_{2} \mathrm{O}_{2}\right)\right] \mathrm{N} \mathrm{O}_{2} \) is \( +3 \)
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