KCET · Chemistry · Aldehydes and Ketones
The reagent with which both acetaldehyde and acetone react is
- A Fehling's solution
- B \(\mathrm{I}_{2} / \mathrm{NaOH}\)
- C Tollen's reagent
- D carbonic acid
Answer & Solution
Correct Answer
(B) \(\mathrm{I}_{2} / \mathrm{NaOH}\)
Step-by-step Solution
Detailed explanation
Due to the presence of

group, acetaldehyde

and acetone

react with iodine in sodium hydroxide to give yellow ppt of iodoform.
\(\mathrm{CH}_{3} \mathrm{CHO}+3 \mathrm{I}_{2}+3 \mathrm{NaOH} \longrightarrow\)
\(\mathrm{Cl}_{3} \mathrm{CHO}+3 \mathrm{NaI}+3 \mathrm{H}_{2} \mathrm{O}\)
\(\mathrm{Cl}_{3} \mathrm{CHO}+\mathrm{NaOH} \longrightarrow \mathrm{CHI}_{3}+\mathrm{HCOONa}\)
\(\mathrm{CH}_{3} \mathrm{COCH}_{3}+3 \mathrm{I}_{2}+3 \mathrm{NaOH} \longrightarrow\)
\(\mathrm{Cl}_{3} \mathrm{COCH}_{3}+3 \mathrm{NaI}+3 \mathrm{H}_{2} \mathrm{O}\)
\(\mathrm{Cl}_{3} \mathrm{COH}_{3}+\mathrm{NaOH} \longrightarrow \mathrm{CHI}_{3}+\mathrm{CH}_{3} \mathrm{COONa}^{-}\)
\(\mathrm{CHI}_{3}\) is Iodoform.

group, acetaldehyde

and acetone

react with iodine in sodium hydroxide to give yellow ppt of iodoform.
\(\mathrm{CH}_{3} \mathrm{CHO}+3 \mathrm{I}_{2}+3 \mathrm{NaOH} \longrightarrow\)
\(\mathrm{Cl}_{3} \mathrm{CHO}+3 \mathrm{NaI}+3 \mathrm{H}_{2} \mathrm{O}\)
\(\mathrm{Cl}_{3} \mathrm{CHO}+\mathrm{NaOH} \longrightarrow \mathrm{CHI}_{3}+\mathrm{HCOONa}\)
\(\mathrm{CH}_{3} \mathrm{COCH}_{3}+3 \mathrm{I}_{2}+3 \mathrm{NaOH} \longrightarrow\)
\(\mathrm{Cl}_{3} \mathrm{COCH}_{3}+3 \mathrm{NaI}+3 \mathrm{H}_{2} \mathrm{O}\)
\(\mathrm{Cl}_{3} \mathrm{COH}_{3}+\mathrm{NaOH} \longrightarrow \mathrm{CHI}_{3}+\mathrm{CH}_{3} \mathrm{COONa}^{-}\)
\(\mathrm{CHI}_{3}\) is Iodoform.
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