KCET · Chemistry · Solid State
A compound of 'A' and 'B' crystallises in a cubic lattice in which 'A' atoms occupy the lattice points at the corners of the cube. The ' \(B\) ' atoms occupy the centre of each face of the cube. The probable empirical formula of the compound is
- A \(\mathrm{AB}_{2}\)
- B \(A_{3} B\)
- C \(\mathrm{AB}\)
- D \(\mathrm{AB}_{3}\)
Answer & Solution
Correct Answer
(D) \(\mathrm{AB}_{3}\)
Step-by-step Solution
Detailed explanation
\(A\) occupies corners, thus number of \(A\) atoms per unit cell \(=8 \times \frac{1}{8}=1\)
\(B\) occupies face centres, thus number of \(B\) atoms per unit cell \(=6 \times \frac{1}{2}=3\)
\(\therefore\) The empirical formula of the compound is \(\mathrm{AB}_{3}\).
\(B\) occupies face centres, thus number of \(B\) atoms per unit cell \(=6 \times \frac{1}{2}=3\)
\(\therefore\) The empirical formula of the compound is \(\mathrm{AB}_{3}\).
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