KCET · Chemistry · Aldehydes and Ketones
\(A, B\) and \(C\) respectively are
- A ethanol, ethane nitrile and ethyne
- B ethane nitrile, ethanol and ethyne
- C ethyne, ethanol and ethane nitrile
- D ethyne, ethane nitrile and ethanol
Answer & Solution
Correct Answer
(C) ethyne, ethanol and ethane nitrile
Step-by-step Solution
Detailed explanation
Ethyne on reaction with \(\mathrm{HgSO}_{4} / \mathrm{H}_{2} \mathrm{SO}_{4}\) gives ethanol (i.e. \(\mathrm{CH}_{2}=\mathrm{CH}-\mathrm{OH}\) ) which interconvert (i.e. tautomerises) to give acetaldehyde \(\left(\mathrm{CH}_{3} \mathrm{CHO}\right)\).
\(\mathrm{PCC}\) is an oxidising agent, which oxidised the alcohol to aldehyde. Therefore, \((B)\) is an alcohol, i.e. ethanol.
\(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH} \stackrel{\mathrm{PCC}}{\longrightarrow} \mathrm{CH}_{3} \mathrm{CHO}\)
Ethane nitrile on reaction with \(\mathrm{SnCl}_{2} / \mathrm{HCl}\) followed by acid hydrolysis give acetaldehyde.
\(\mathrm{PCC}\) is an oxidising agent, which oxidised the alcohol to aldehyde. Therefore, \((B)\) is an alcohol, i.e. ethanol.
\(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH} \stackrel{\mathrm{PCC}}{\longrightarrow} \mathrm{CH}_{3} \mathrm{CHO}\)
Ethane nitrile on reaction with \(\mathrm{SnCl}_{2} / \mathrm{HCl}\) followed by acid hydrolysis give acetaldehyde.
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