KCET · Chemistry · Some Basic Concepts of Chemistry
0.48 g of an organic compound on complete combustion produced 0.22 g of \(\mathrm{CO}_2\). The percentage of C in the given organic compound is
- A \(25\)
- B \(50\)
- C \(12.5\)
- D \(87.5\)
Answer & Solution
Correct Answer
(C) \(12.5\)
Step-by-step Solution
Detailed explanation
Given,
Mass of organic compound \(=0.48 \mathrm{~g}\)
Mass of \(\mathrm{CO}_2\) produced \(=0.22 \mathrm{~g}\)
\% C =?
Using formula
\(\% \mathrm{C}=\frac{12}{44} \times \frac{\text { mass of } \mathrm{CO}_2}{\text { mass of organic compound }} \times 100\)
\(=\frac{12}{44} \times \frac{0.22}{0.48} \times 100\)
\(=12.5 \%\)
Mass of organic compound \(=0.48 \mathrm{~g}\)
Mass of \(\mathrm{CO}_2\) produced \(=0.22 \mathrm{~g}\)
\% C =?
Using formula
\(\% \mathrm{C}=\frac{12}{44} \times \frac{\text { mass of } \mathrm{CO}_2}{\text { mass of organic compound }} \times 100\)
\(=\frac{12}{44} \times \frac{0.22}{0.48} \times 100\)
\(=12.5 \%\)
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