KCET · Chemistry · Hydrocarbons
The reagent used in Clemmensen's reduction is
- A conc. \(\mathrm{H}_{2} \mathrm{SO}_{4}\)
- B \(\mathrm{Zn}-\mathrm{Hg}\) conc. \(\mathrm{HCl}\)
- C \(a q \mathrm{KOH}\)
- D alc. \(\mathrm{KOH}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{Zn}-\mathrm{Hg}\) conc. \(\mathrm{HCl}\)
Step-by-step Solution
Detailed explanation
In Clemmensen's reduction
\(\mathrm{Zn}-\mathrm{Hg} /\) conc. \(\mathrm{HCl}\) is used.
\(>\mathrm{C}=\mathrm{O}+4 \mathrm{H} \stackrel{\mathrm{Zn}-\mathrm{Hg}+\text { conc. } \mathrm{HCl}}{\longrightarrow} \mathrm{CH}_{2}+\mathrm{H}_{2} \mathrm{O}\)
This method is used to convert carbonyl compound into alkane.
\(\mathrm{Zn}-\mathrm{Hg} /\) conc. \(\mathrm{HCl}\) is used.
\(>\mathrm{C}=\mathrm{O}+4 \mathrm{H} \stackrel{\mathrm{Zn}-\mathrm{Hg}+\text { conc. } \mathrm{HCl}}{\longrightarrow} \mathrm{CH}_{2}+\mathrm{H}_{2} \mathrm{O}\)
This method is used to convert carbonyl compound into alkane.
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