JEE Mains · Maths · STD 11 - 6. permutation and combination
The total number of numbers, lying between \(100\) and \(1000\) that can be formed with the digits \(1,2,3,4,5,\) if the repetition of digits is not allowed and numbers are divisible by either \(3\) or \(5,\) is ...........
- A \(32\)
- B \(64\)
- C \(25\)
- D \(40\)
Answer & Solution
Correct Answer
(A) \(32\)
Step-by-step Solution
Detailed explanation
We need three digits numbers. Since \(1+2+3+4+5=15\) So, number of possible triplets for multiple of 15 is \(1 \times 2 \times 2\) so Ans. \(4 \times\lfloor 3+4 \times 3-1 \times 2 \times\lfloor 2=32\)
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