JEE Mains · Physics · STD 12 - 12. atoms
The time period of revolution of electron in its ground state orbit in a hydrogen atom is \(1.6 \times 10^{-16} \;\mathrm{s}\). The frequency of revolution of the electron in its first excited state (in \(s^{-1}\) ) is:
- A \(6.2 \times 10^{15}\)
- B \(5.6 \times 10^{12}\)
- C \(7.8 \times 10^{14}\)
- D \(1.6 \times 10^{14}\)
Answer & Solution
Correct Answer
(C) \(7.8 \times 10^{14}\)
Step-by-step Solution
Detailed explanation
Time period of revolution of electron in \(\mathrm{n}^{\text {th }}\) orbit \(\mathrm{T}=\frac{2 \pi \mathrm{r}}{\mathrm{V}}=\frac{2 \pi \mathrm{a}_{0}\left(\frac{\mathrm{n}^{2}}{\mathrm{Z}}\right)}{\mathrm{V}_{0}\left(\frac{\mathrm{Z}}{\mathrm{n}}\right)}\)…
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