JEE Mains · Maths · STD 11 - 8. sequence and series
The sum of the following series \(1 + 6 + \frac{{9({1^2} + {2^2} + {3^2})}}{7} + \frac{{12({1^2} + {2^2} + {3^2} + {4^2})}}{9} + \frac{{15({1^2} + {2^2} + .... + {5^2})}}{{11}} + ...\) up to \(15\) terms, is
- A \(7820\)
- B \(7830\)
- C \(7520\)
- D \(7510\)
Answer & Solution
Correct Answer
(A) \(7820\)
Step-by-step Solution
Detailed explanation
\({T_n} = \frac{{\left( {3 + \left( {n - 1} \right) \times 3} \right)\left( {{1^2} + {2^2} + ... + {n^2}} \right)}}{{\left( {2n + 1} \right)}}\)…
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