JEE Mains · Physics · STD 12 - 3. current electricity
If you are provided a set of resistances \(2\, \Omega, 4\, \Omega\) \(6\, \Omega\) and \(8\, \Omega\). Connect these resistances so as to obtain an equivalent resistance of \(\frac{46}{3}\, \Omega\).
- A \(4 \,\Omega\) and \(6 \,\Omega\) are in parallel with \(2 \,\Omega\) and \(8 \,\Omega\) in series
- B \(6 \,\Omega\) and \(8 \,\Omega\) are in parallel with \(2 \,\Omega\) and \(4 \,\Omega\) in series
- C \(2 \,\Omega\) and \(6\, \Omega\) are in parallel with \(4 \,\Omega\) and \(8 \,\Omega\) in series
- D \(2\, \Omega\) and \(4 \,\Omega\) are in parallel with \(6 \,\Omega\) and \(8 \,\Omega\) in series
Answer & Solution
Correct Answer
(D) \(2\, \Omega\) and \(4 \,\Omega\) are in parallel with \(6 \,\Omega\) and \(8 \,\Omega\) in series
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