JEE Mains · Maths · STD 12 - 11. three dimension geometry
The distance of the point \(Q(0,2,-2)\) form the line passing through the point \(\mathrm{P}(5,-4,3)\) and perpendicular to the lines \(\overrightarrow{\mathrm{r}}=(-3 \hat{\mathrm{i}}+2 \hat{\mathrm{k}})\) \(\lambda(2 \hat{\mathrm{i}}+3 \hat{\mathrm{j}}+5 \hat{\mathrm{k}}), \lambda \in \mathbb{R}\) and \( \overrightarrow{\mathrm{r}}=(\hat{\mathrm{i}}-2 \hat{\mathrm{j}}+\hat{\mathrm{k}})+\) \(\mu(-\hat{i}+3 \hat{J}+2 \hat{K}), \mu \in \mathbb{R}\) is
- A \(\sqrt{86}\)
- B \(\sqrt{20}\)
- C \(\sqrt{54}\)
- D \(\sqrt{74}\)
Answer & Solution
Correct Answer
(D) \(\sqrt{74}\)
Step-by-step Solution
Detailed explanation
A vector in the direction of the required line can be obtained by cross product of \(\left|\begin{array}{ccc}\hat{\mathrm{i}} & \hat{\mathrm{j}} & \hat{\mathrm{k}} \\ 2 & 3 & 5 \\ -1 & 3 & 2\end{array}\right|\) Required line,…
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