JEE Mains · Physics · STD 12 - Ray optics and optical instruments
- JEE Mains 2023
- Hard
- Numerical
A point object, \(O\) is placed in front of two thin symmetrical coaxial convex lenses \(L _1\) and \(L _2\) with focal length \(24\,cm\) and \(9\,cm\) respectively. The distance between two lenses is \(10\,cm\) and the object is placed \(6\,cm\) away from lens \(L _1\) as shown in the figure. The distance between the object and the image formed by the system of two lenses is .........\(cm\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(34\)
Step-by-step Solution
Detailed explanation
\(\text { From Ist lens } \frac{1}{ v }+\frac{1}{6}=\frac{1}{24}\)
\(\frac{1}{ v } =\frac{1}{24}-\frac{1}{6}=-\frac{1}{8}\)
\(v =-8\,cm\)
From \(IInd\) lens \(\frac{1}{ v } +\frac{1}{18}=\frac{1}{9}\)
\(\frac{1}{ v }= \frac{1}{18}\)
\(v =18\)
So distance between object and its image
\(=6+10+18=34\,cm\)
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