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JEE Mains · Physics · STD 12 -Alternating current
  • JEE Mains 2022
  • Hard
  • MCQ

A sinusoidal voltage \(V(t)=210\,\sin 3000 t\) volt is applied to a series \(LCR\) circuit in which \(L =10\) \(mH , C =25 \mu F\) and \(R =100 \Omega\). The phase difference \((\Phi)\) between the applied voltage and resultant current will be

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Answer & Solution

Correct Answer

(A) \(\tan ^{-1}(0.17)\)

Step-by-step Solution

Detailed explanation

\(X _{ L }=10^{-2} \times 3000=30 \Omega\)

\(X _{ C }=\frac{1}{3000 \times 25 \times 10^{-6}}=\frac{40}{3} \Omega\)

\(X = X _{ L }- X _{ C }\)

\(=30-\frac{40}{3}=\frac{50}{3}\)

\(\tan \delta=\frac{ X }{ R }=\frac{50}{3 \times 100}=\frac{1}{6}\)

\(\delta=\tan ^{-1}\left(\frac{1}{6}\right)=\tan ^{-1}(0.17)\)

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