JEE Mains · Maths · STD 11 - 6. permutation and combination
If \(\mathrm{n}\) is the number of ways five different employees can sit into four indistinguishable offices where any office may have any number of persons including zero, then \(\mathrm{n}\) is equal to :
- A \(47\)
- B \(53\)
- C \(51\)
- D \(43\)
Answer & Solution
Correct Answer
(C) \(51\)
Step-by-step Solution
Detailed explanation
Total ways to partition \(5\)into \(4\) parts are : \(5,0,0,0 \Rightarrow 1\) Ways \(4,1,0,0 \Rightarrow \frac{5 !}{4 !}=5\) \(3,2,0,0, \Rightarrow \frac{5 !}{3 ! 2 !}=10\) ways \(2,2,0,1 \Rightarrow \frac{5 !}{2 ! 2 ! 2 !}=15\) ways…
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