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JEE Mains · Maths · STD 11 - 7. binomial theoram
The term independent of \(x\) in the expansion of \(\left[\frac{x+1}{x^{2 / 3}-x^{1 / 3}+1}-\frac{x-1}{x-x^{1 / 2}}\right]^{10}, x \neq 1,\) is equal to ....... .
- A \(240\)
- B \(225\)
- C \(210\)
- D \(196\)
Answer & Solution
Correct Answer
(C) \(210\)
Step-by-step Solution
Detailed explanation
\(\left.\left( x ^{1 / 3}+1\right)-\left(\frac{\sqrt{ x }+1}{\sqrt{ x }}\right)\right)^{10}\) \(\left( x ^{1 / 3}- x ^{-1 / 2}\right)^{10}\) \(T _{ r +1}={ }^{10} C _{ r }\left( x ^{1 / 3}\right)^{10- r }\left(- x ^{-1 / 2}\right)^{ r }\)…
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