JEE Mains · Maths · STD 11 - 8. sequence and series
Let \(a\), \(b\) be two non-zero real numbers. If \(p\) and \(r\) are the roots of the equation \(x ^{2}-8 ax +2 a =0\) and \(q\) and \(s\) are the roots of the equation \(x^{2}+12 b x+6 b\) \(=0\), such that \(\frac{1}{ p }, \frac{1}{ q }, \frac{1}{ r }, \frac{1}{ s }\) are in A.P., then \(a ^{-1}- b ^{-1}\) is equal to \(......\)
- A \(37\)
- B \(36\)
- C \(38\)
- D \(32\)
Answer & Solution
Correct Answer
(C) \(38\)
Step-by-step Solution
Detailed explanation
\(x ^{2}-8 ax +2 a =0\) \(p + r =8 a\) \(pr =2 a\) \(\frac{1}{ p }+\frac{1}{ r }=4\) \(\frac{2}{ q }=4\) \(q =\frac{1}{2}\) \(p =\frac{1}{5}\) \(x^{2}+12 b x+6 b=0\) \(q+s=-12 b\) \(q s=6 b\) \(\frac{1}{q}+\frac{1}{s}=-2\) \(\frac{2}{r}=-2\) \(r=-1\) \(s=\frac{-1}{4}\)…
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