JEE Mains · Physics · STD 11 - Motion in plane
- JEE Mains 2021
- Hard
- MCQ
A particle is moving with uniform speed along the circumference of a circle of radius \(R\) under the action of a central fictitious force \(F\) which is inversely proportional to \(R ^{3}\). Its time period of revolution will be given by
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(T \propto R ^{2}\)
Step-by-step Solution
Detailed explanation
\(F \propto \frac{1}{R^{3}}\)
\(\frac{K}{R^{3}}=m \omega^{2} R\)
\(\omega^{2}=\frac{K}{m} \times \frac{1}{R^{4}}\)
\(\left(\frac{2 \pi}{T}\right)^{2}=\frac{K}{m} \times \frac{1}{R^{4}}\)
\(T^{2} \propto R^{4}\)
\(T \propto R^{2}\)
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