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JEE Mains · Physics · STD 11 - 3.2 motion in plane

A particle is moving with uniform speed along the circumference of a circle of radius \(R\) under the action of a central fictitious force \(F\) which is inversely proportional to \(R ^{3}\). Its time period of revolution will be given by

  1. A \(T \propto R ^{2}\)
  2. B \(T \propto R ^{\frac{3}{2}}\)
  3. C \(T \propto R ^{\frac{5}{2}}\)
  4. D \(T \propto R ^{\frac{4}{3}}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(T \propto R ^{2}\)

Step-by-step Solution

Detailed explanation

\(F \propto \frac{1}{R^{3}}\) \(\frac{K}{R^{3}}=m \omega^{2} R\) \(\omega^{2}=\frac{K}{m} \times \frac{1}{R^{4}}\) \(\left(\frac{2 \pi}{T}\right)^{2}=\frac{K}{m} \times \frac{1}{R^{4}}\) \(T^{2} \propto R^{4}\) \(T \propto R^{2}\)
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