JEE Mains · Physics · STD 12 - 5. Magnetism and matter
A paramagnetic sample shows a net magnetisation of \(6 \,A / m\) when it is placed in an external magnetic field of \(0.4 \,T\) at a temperature of \(4\, K\). When the sample is placed in an external magnetic field of \(0.3\, T\) at a temperature of \(24\, K\), then the magnetisation will be\(......A/m\)
- A \(4\)
- B \(0.75\)
- C \(2.25\)
- D \(1\)
Answer & Solution
Correct Answer
(B) \(0.75\)
Step-by-step Solution
Detailed explanation
For paramagnetic material According to curies law \(x \propto \frac{1}{ T }\) \(\chi \propto \frac{1}{ T } \Rightarrow \chi_{1} T _{1}=\chi_{2} T _{2}\) \(\Rightarrow \frac{6}{0.4} \times 4=\frac{ I }{0.3} \times 24\) \(I =\frac{0.3}{0.4}=0.75 A / m\)
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