JEE Mains · Physics · STD 12 - 5. Magnetism and matter
A hoop and a solid cylinder of same mass and radius are made of a permanent magnetic material with their magnetic moment parallel to their respective axes. But the magnetic moment of hoop is twice of solid cylinder. They are placed in a uniform magnetic field in such a manner that their magnetic moments make a small angle with the field. If the oscillation periods of hoop and cylinder are \(T_h\) and \(T_c\) respectively, then the relation between them is....
- A \(T_h = T_c\)
- B \(T_h = 2T_c\)
- C \(T_h = 1.5T_c\)
- D \(T_h = 0.5T_c\)
Answer & Solution
Correct Answer
(A) \(T_h = T_c\)
Step-by-step Solution
Detailed explanation
\(\because \quad \mathrm{T}=2 \pi \sqrt{\frac{1}{\mu \mathrm{B}}}\) \(\frac{T_{h}}{T_{c}} =\sqrt{\frac{I_{R}}{I_{c}} \times \frac{\mu_{c}}{\mu_{h}}} \) \(=\sqrt{2 \times \frac{1}{2}}=1\) \(T_{h} =T_{c}\)
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