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JEE Mains · Physics · STD 12 - Magnetism and matter
  • JEE Mains 2019
  • Medium
  • MCQ

A hoop and a solid cylinder of same mass and radius are made of a permanent magnetic material with their magnetic moment parallel to their respective axes. But the magnetic moment of hoop is twice of solid cylinder. They are placed in a uniform magnetic field in such a manner that their magnetic moments make a small angle with the field. If the oscillation periods of hoop and cylinder are \(T_h\) and \(T_c\) respectively, then the relation between them is....

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Answer & Solution

Correct Answer

(A) \(T_h = T_c\)

Step-by-step Solution

Detailed explanation

\(\because \quad \mathrm{T}=2 \pi \sqrt{\frac{1}{\mu \mathrm{B}}}\)

\(\frac{T_{h}}{T_{c}} =\sqrt{\frac{I_{R}}{I_{c}} \times \frac{\mu_{c}}{\mu_{h}}} \)

\(=\sqrt{2 \times \frac{1}{2}}=1\)

\(T_{h} =T_{c}\)