JEE Mains · Maths · STD 12 - 5. continuity and differentiation
For \(x \in R\) , \(f\left( x \right) = \left| {\log 2 - \sin x} \right|\) and \(g\left( x \right) = f\left( {f\left( x \right)} \right)\) then .. .
- A \(g'\left( 0 \right) = - \cos \left( {\log 2} \right)\)
- B \(g\) is differentiable at \(x=0 \) and \(g'\left( 0 \right) = - \sin \left( {\log 2} \right)\)
- C \(g\) is not differentiable at \(x=0 \)
- D \(\;g'\left( 0 \right) = \cos \left( {\log 2} \right)\)
Answer & Solution
Correct Answer
(C) \(g\) is not differentiable at \(x=0 \)
Step-by-step Solution
Detailed explanation
In the neighbourhood of \(x = 0\), \(f(x) = log2 -sinx\) \( g(x) = f(f(x)) = log2 -sin(f(x))\) \(= log2 -sin(log2 -sinx)\) It is differentiable at \(x = 0,\) so \( g'(x) = -cos(log2 -sinx) (-cosx)\) \(g'(0) = cos(log2)\)
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