JEE Mains · Maths · STD 12 - 11. three dimension geometry
A plane containing the point \((3, 2, 0)\) and the line \(\frac{{x - 1}}{1} = \frac{{y - 2}}{5} = \frac{{z - 3}}{4}\) also contains the point
- A \((0, 3, 1)\)
- B \((0, 7, -10)\)
- C \((0, -3, 1)\)
- D \((0, 7, 10)\)
Answer & Solution
Correct Answer
(C) \((0, -3, 1)\)
Step-by-step Solution
Detailed explanation
Equation of the plane containing the given line \(\frac{x-1}{1}=\frac{y-2}{5}=\frac{z-3}{4}\) is \(A(x-1)+B(y-2)+C(z-3)=0\) ....\((i)\) where \(\mathrm{A}+5 \mathrm{B}+4 \mathrm{C}=0\) ,,,\((ii)\) Since the point \((3,2,0)\) contains in theplane (i), therefore…
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