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JEE Mains · Maths · STD 11 - Trigonometrical equations

Two vertical poles \(AB =15 m\) and \(CD =10 m\) are standing apart on a horizontal ground with points \(A\) and \(C\) on the ground. If \(P\) is the point of intersection of \(BC\) and \(AD ,\) then the height of \(P\) (in \(m\) ) above the line \(AC\) is 

  1. A \(\frac{20}{3}\)
  2. B \(5\)
  3. C \(\frac{10}{3}\)
  4. D \(6\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(6\)

Step-by-step Solution

Detailed explanation

\(\tan \theta=\frac{10}{x}=\frac{h}{x_{2}} \Rightarrow x_{2}=\frac{h x}{10}\) \(\tan \phi=\frac{15}{x}=\frac{h}{x_{1}} \Rightarrow x_{1}=\frac{h x}{15}\) Now, \(x_{1}+x_{2}=x=\frac{h x}{15}+\frac{h x}{10}\) \(\Rightarrow 1=\frac{h}{10}+\frac{h}{15} \Rightarrow h=6\)
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