JEE Mains · Maths · STD 11 - 6. permutation and combination
Total numbers of \(3-\)digit numbers that are divisible by 6 and can be formed by using the digits \(1, 2, 3, 4,5\) with repetition, is \(.......\).
- A \(15\)
- B \(16\)
- C \(14\)
- D \(13\)
Answer & Solution
Correct Answer
(B) \(16\)
Step-by-step Solution
Detailed explanation
For number to be divisible by '\(6\)' unit digit should be even and sum of digit is divisible by \(3.\) \((2,1,3),(2,3,4),(2,5,5),(2,2,5),(2,2,2)\) \((4,1,1),(4,4,1),(4,4,4),(4,3,5)\) \(2,1,3 \Rightarrow 312,132\) \(2,3,4 \Rightarrow 342,432,234,324\) \(2,5,5 \Rightarrow 552\)…
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