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JEE Mains · Maths · STD 11 - 6. permutation and combination

There are ten boys \(B_{1}, B_{2}, \ldots ., B_{10}\) and five girls \(G_{1}\), \(G _{2}, \ldots, G _{5}\) in a class. Then the number of ways of forming a group consisting of three boys and three girls, if both \(B_{1}\) and \(B_{2}\) together should not be the members of a group, is

  1. A \(1119\)
  2. B \(1120\)
  3. C \(1121\)
  4. D \(1122\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(1120\)

Step-by-step Solution

Detailed explanation

\(n ( B )=10\) \(n ( a )=5\) The number of ways of forming a group of \(3\) girls of \(3\) boys. \(={ }^{10} C _{3} \times{ }^{5} C _{3}\) \(=\frac{10 \times 9 \times 8}{3 \times 2} \times \frac{5 \times 4}{2}=1200\) The number of ways when two particular boys \(B_{1}\) of…