JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations
The number of real solutions of the equation \(x\left(x^2+3|x|+5|x-1|+6|x-2|\right)=0\) is
- A \(5\)
- B \(3\)
- C \(4\)
- D \(1\)
Answer & Solution
Correct Answer
(D) \(1\)
Step-by-step Solution
Detailed explanation
\(x=0 \text { and } x^2+3|x|+5|x-1|+6|x-2|=0\) Here all terms are \(+v e\) except at \(x=0\) So there is no value of \(x\) Satisfies this equation Only solution \(\mathrm{x}=0\) No of solution 1 .
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