JEE Mains · Maths · STD 12 - 10. vector algebra
Let three vectors \(\overrightarrow{\mathrm{a}}=\alpha \hat{\mathrm{i}}+4 \hat{\mathrm{j}}+2 \hat{\mathrm{k}}\), \(\vec{b}=5 \hat{i}+3 \hat{j}+4 \hat{k}, \vec{c}=x \hat{i}+y \hat{j}+z \hat{k}\) from a triangle such that \(\overrightarrow{\mathrm{c}}=\overrightarrow{\mathrm{a}}-\overrightarrow{\mathrm{b}}\) and the area of the triangle is \(5 \sqrt{6}\). if \(\alpha\) is a positive real number, then \(|\overrightarrow{\mathrm{c}}|^2\) is :
- A \(16\)
- B \(14\)
- C \(12\)
- D \(10\)
Answer & Solution
Correct Answer
(B) \(14\)
Step-by-step Solution
Detailed explanation
\( \overrightarrow{\mathrm{c}}=\overrightarrow{\mathrm{a}}-\overrightarrow{\mathrm{b}} \) \( \Rightarrow(\mathrm{x}, \mathrm{y}, \mathrm{z})=(\alpha-5,1,-2) \) \( \Rightarrow \mathrm{x}=\alpha-5, \mathrm{y}=1, \mathrm{z}=-2\) .............(\(1\)) Area of \(\Delta=5 \sqrt{6}\)…
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