JEE Mains · Maths · STD 11 - 7. binomial theoram
The sum of the coefficient of \(x^{2 / 3}\) and \(x^{-2 / 5}\) in the binomial expansion of \(\left(x^{2 / 3}+\frac{1}{2} x^{-2 / 5}\right)^9\) is :
- A \(21 / 4\)
- B \(69 / 16\)
- C \(63 / 16\)
- D \(19 / 4\)
Answer & Solution
Correct Answer
(A) \(21 / 4\)
Step-by-step Solution
Detailed explanation
\( \mathrm{T}_{\mathrm{r}+1}={ }^9 \mathrm{C}_{\mathrm{r}}\left(\mathrm{x}^{2 / 3}\right)^{9-\mathrm{r}}\left(\frac{\mathrm{x}^{-2 / 3}}{2}\right)^{\mathrm{r}} \)…
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