JEE Mains · Maths · STD 11 - 8. sequence and series
An arithmetic progression is written in the following way
The sum of all the terms of the \(10^{\text {th }}\) row is ..........
- A \(1505\)
- B \(1078\)
- C \(1045\)
- D \(1548\)
Answer & Solution
Correct Answer
(A) \(1505\)
Step-by-step Solution
Detailed explanation
\( 2,5,11,20, \ldots . . \) \( \text { General term }=\frac{3 n^2-3 n+4}{2} \) \( \mathrm{T}_{10}=\frac{3(100)-3(10)+4}{2} \) \(=137 \) \( 10 \text { terms with c.d. }=3\) sum \( =\frac{10}{2}(2(137)+9(3))\) \( =1505\)
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