JEE Mains · Maths · STD 11 - 9. straight line
Let ABC be the triangle such that the equations of lines \(A B\) and \(A C\) be \(3 y-x=2\) and \(x+y=2\), respectively, and the points B and C lie on x -axis. If \(P\) is the orthocentre of the triangle \(A B C\), then the area of the triangle PBC is equal to
- A 4
- B 10
- C 8
- D 6
Answer & Solution
Correct Answer
(D) 6
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Equation of Altitude } \mathrm{AP}: \mathrm{x}=1 \\ & \text { Equation of Altitude } \mathrm{BP}: \mathrm{y}-0=1(\mathrm{x}+2) \\ & \Rightarrow \mathrm{x}=1 \& \\ & \mathrm{x}-\mathrm{y}+2=0 \\ & \mathrm{P}(1,3) \\ & \text { Area of } \triangle…
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