JEE Mains · Maths · STD 11 - 7. binomial theoram
The sum of the co-efficients of all odd degree terms in the expansion of \({\left( {x + \sqrt {{x^3} - 1} } \right)^5} + {\left( {x - \sqrt {{x^3} - 1} } \right)^5},\left( {x > 1} \right)\)
- A \(0\)
- B \(1\)
- C \(2\)
- D \(-1\)
Answer & Solution
Correct Answer
(C) \(2\)
Step-by-step Solution
Detailed explanation
\((C)\) Since we know that, \({(x+a)^{5}+(x-a)^{5}}\) \({=2\left[^{5} C_{0} x^{5}+^{5} C_{2} x^{3} \cdot a^{2}+^{5} C_{4} x \cdot a^{4}\right]}\) \(\therefore \quad(x+\sqrt{x^{3}-1})^{5}+(x-\sqrt{x^{3}-1})^{5}\)…
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