JEE Mains · Maths · STD 11 - Trigonometrical equations
The number of distinct solutions of the equation \(\log _{\frac{1}{2}}|\sin x|=2-\log _{\frac{1}{2}}|\cos x|\) in the interval \([0,2 \pi],\) is
- A \(8\)
- B \(5\)
- C \(11\)
- D \(12\)
Answer & Solution
Correct Answer
(A) \(8\)
Step-by-step Solution
Detailed explanation
\(\log _{1 / 2}|\sin x|=2-\log _{1 / 2}|\cos x| ; x \in[0,2 \pi]\) \(\Rightarrow \quad \log _{1 / 2}|\sin x|+\log _{1 / 2}|\cos x|=2\) \(\Rightarrow \log _{1 / 2}(|\sin x \cos x|)=2\) \(\Rightarrow \quad|\sin x \cos x|=\frac{1}{4} \quad \Rightarrow|\sin 2 x|=\frac{1}{2}\) \(=8\)…
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