ExamBro
ExamBro
JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations

If \(\alpha \) and \( \beta \) are roots of the equation, \({x^2} - 4\sqrt 2\,kx + 2\,{e^{4\ln \,k}} - 1 = 0\) for some \(k\), and \({\alpha ^2} + {\beta ^2} = 66\), then \({\alpha ^3} + {\beta ^3}\) is equal to 

  1. A \(248\sqrt 2 \)
  2. B \(280\sqrt 2 \)
  3. C \(-32\sqrt 2 \)
  4. D \(-280\sqrt 2 \)
Verified Solution

Answer & Solution

Correct Answer

(D) \(-280\sqrt 2 \)

Step-by-step Solution

Detailed explanation

\(x^{2}-4 \sqrt{2} k x+2 e^{4 \ln k}-1=0\) or, \(x^{2}-4 \sqrt{2} k x+2 k^{4}-1=0\) \(\alpha+\beta=4 \sqrt{2} k\) and \(\alpha . \beta=2 k^{4}-1\) Squaring both sides, we get \((\alpha+\beta)^{2}=(4 \sqrt{2} k)^{2}\) \(\Rightarrow \alpha^{2}+\beta^{2}+2 \alpha \beta=32 k^{2}\)…
From JEE Mains
Explore more questions on app