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JEE Mains · Maths · STD 11 - 6. permutation and combination

The number of ways of selecting \(15\) teams from \(15\) men and \(15\) women, such that each team consists of a man and a woman, is

  1. A \(1120\)
  2. B \(1880\)
  3. C \(1960\)
  4. D \(1240\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(1240\)

Step-by-step Solution

Detailed explanation

Number of ways of selecting a man and a woman for a team from \(15\) men \(15\) women \(=15\times 15=(15)^2\) Number of ways of selecting a man and a woman for next team out of the remaining \(14\) men \(14\) women. \(=14\times 14=(14)^2\) Similarly for other teams Hence…