JEE Mains · Maths · STD 11 - 12. limits
If \(\operatorname{Lim}_{x \rightarrow 0}\left(\frac{\tan x}{x}\right)^{\frac{1}{x^2}}=p\), then \(96 \log _e p\) is equal to ______
- A 30
- B 34
- C 32
- D 36
Answer & Solution
Correct Answer
(C) 32
Step-by-step Solution
Detailed explanation
\(P=\lim _{x \rightarrow 0}\left(\frac{\tan x}{x}\right)^{\frac{1}{x^2}}\) \(\Rightarrow \mathrm{P}=\mathrm{e}^{\lim _{\mathrm{x} \rightarrow 0}\left(\frac{\tan x-\mathrm{x}}{\mathrm{x}^3}\right)}\)…
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