JEE Mains · Maths · STD 11 - 7. binomial theoram
The number of terms in the expansion of \((1 +x)^{101} (1 +x^2 - x)^{100}\) in powers of \(x\) is
- A \(302\)
- B \(301\)
- C \(202\)
- D \(101\)
Answer & Solution
Correct Answer
(C) \(202\)
Step-by-step Solution
Detailed explanation
Given expansion is \((1+x)^{101}\left(1-x+x^{2}\right)^{100}\) \(=(1+x)(1+x)^{100}\left(1-x+x^{2}\right)^{100}\) \(=(1+x)\left[(1+x)\left(1-x+x^{2}\right)\right]^{100}\) \(=(1+x)\left[\left(1-x^{3}\right)^{100}\right]\) Expansion \(\left(1-x^{3}\right)^{100}\) will have…
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