JEE Mains · Maths · STD 11 - 9. straight line
Let the circumcentre of a triangle with vertices \(A ( a , 3), B ( b , 5)\) and \(C ( a , b ), ab >0\) be \(P (1,1)\). If the line \(AP\) intersects the line \(BC\) at the point \(Q \left( k _{1}, k _{2}\right)\), then \(k _{1}+ k _{2}\) is equal to.
- A \(2\)
- B \(\frac{4}{7}\)
- C \(\frac{2}{7}\)
- D \(4\)
Answer & Solution
Correct Answer
(B) \(\frac{4}{7}\)
Step-by-step Solution
Detailed explanation
\(m _{ AC } \longrightarrow \infty\) \(m _{ PD }=0\) \(D \left(\frac{ a + a }{2}, \frac{ b +3}{2}\right)\) \(D \left( a , \frac{ b +3}{2}\right)\) \(m _{ PD }=0\) \(\frac{ b +3}{2}-1=0\) \(b +3-2=0\) \(b =-1\)…
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