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JEE Mains · Maths · STD 11 - 14. probability

Let \(E\) and \(F\) be two independent events. The probability that both \(E\) and \(F\) happen is \(\frac{1}{12}\) and the probability that neither \(E\) nor \(F\) happens is  \(\frac{1}{2}\) , then a value of  \(\frac{{P(E)}}{{P\left( F \right)}}\) is

  1. A \(\frac{4}{3}\)
  2. B \(\frac{3}{2}\)
  3. C \(\frac{1}{3}\)
  4. D \(\frac{5}{12}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{4}{3}\)

Step-by-step Solution

Detailed explanation

\(P\left( {E \cap F} \right) = P(E) \cdot P(F) = \frac{1}{{12}}\) \(P\left( {\bar E \cap \bar F} \right) = P(\bar E) \cdot P(\bar F) = \frac{1}{2}\) \((1-P(E))(1-P(F))=\frac{1}{2}\) Let \(P(E)=x\) \(P(F) =y \) \(=1-x-y+x y=\frac{1}{2}\)…
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