JEE Mains · Maths · STD 11 - 6. permutation and combination
The number of numbers between \(2,000\) and \(5,000\) that can be formed with the digits \(0, 1, 2, 3, 4,\) (repetition of digits is not allowed) an are multiple of \(3\) is?
- A \(30\)
- B \(48\)
- C \(24\)
- D \(36\)
Answer & Solution
Correct Answer
(A) \(30\)
Step-by-step Solution
Detailed explanation
The thousands place can only be filled with \(2,3\) or \(4\), since the number is greater than \(2000\). For the remaining \(3\) places. we have pick out dights such that the resultant number is divisible by \(3\). It the sum of digits of the number is divisible by \(3,\) then…
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