JEE Mains · Maths · STD 11 - 6. permutation and combination
Let the set \(\mathrm{S}=\{2,4,8,16, \ldots . .512\}\) be partitioned into \(3\) sets \(A, B, C\) with equal number of elements such that \(\mathrm{A} \cup \mathrm{B} \cup \mathrm{C}=\mathrm{S}\) and \(\mathrm{A} \cap \mathrm{B}=\mathrm{B} \cap \mathrm{C}=\mathrm{A} \cap \mathrm{C}=\phi\). The maximum number of such possible partitions of \(S\) is equal to :
- A \(1680\)
- B \(1520\)
- C \(1710\)
- D \(1640\)
Answer & Solution
Correct Answer
(A) \(1680\)
Step-by-step Solution
Detailed explanation
\(\frac{9 !}{(3 ! 3 ! 3 !) 3 !} \times 3 !\)
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