JEE Mains · Maths · STD 11 - 6. permutation and combination
The number of \(6\) digit numbers that can be formed using the digits \(0, 1, 2, 5, 7\) and \(9\) which are divisible by \(11\) and no digits is repeated, is
- A \(36\)
- B \(60\)
- C \(72\)
- D \(48\)
Answer & Solution
Correct Answer
(B) \(60\)
Step-by-step Solution
Detailed explanation
Let the six digit number be \(abcdef\) for this number to be divisible by \(11\) \(|(a+c+e)-(b+d+f)|\) must be multiple of \(11\) \(\therefore \) possibility is \(a+c+c=b+d+f=12\) Case \(I\,\,\{a,c,e\}=\{7,5,0\}\) and \(\{b,d,f\}=\{9,2,1\}\) So, number of numbers…
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