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JEE Mains · Maths · STD 11 - 6. permutation and combination

The number of \(6\) digit numbers that can be formed using the digits \(0, 1, 2, 5, 7\) and \(9\) which are divisible by \(11\) and no digits is repeated, is

  1. A \(36\)
  2. B \(60\)
  3. C \(72\)
  4. D \(48\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(60\)

Step-by-step Solution

Detailed explanation

Let the six digit number be \(abcdef\) for this number to be divisible by \(11\) \(|(a+c+e)-(b+d+f)|\) must be multiple of \(11\) \(\therefore \) possibility is \(a+c+c=b+d+f=12\) Case \(I\,\,\{a,c,e\}=\{7,5,0\}\) and \(\{b,d,f\}=\{9,2,1\}\) So, number of numbers…
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