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JEE Mains · Maths · STD 11 - 9. straight line
A light ray emerging from the point source placed at \(P( 1, 3)\) is reflected at a point \(Q\) in the axis of \(x\). If the reflected ray passes through the point \(R\) (\(6, 7)\), then the abscissa of \(Q\) is
- A \(1\)
- B \(3\)
- C \(\frac{7}{2}\)
- D \(\frac{5}{2}\)
Answer & Solution
Correct Answer
(D) \(\frac{5}{2}\)
Step-by-step Solution
Detailed explanation
Let abcissa of \(Q=x\) \(\therefore \) \(Q=(x,0)\) \(\tan \,\theta = \frac{{0 - 7}}{{x - 6}},\tan \left( {{{180}^o} - \theta } \right) = \frac{{0 - 3}}{{x - 1}}\) Now, \(\tan \left( {{{180}^o} - \theta } \right) = - \tan \,\theta \)…
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