JEE Mains · Maths · STD 11 - 10.1 circle and system of circle
If the four distinct points \((4,6),(-1,5),(0,0)\) and \((\mathrm{k}, 3 \mathrm{k})\) lie on a circle of radius r , then \(10 \mathrm{k}+\mathrm{r}^2\) is equal to
- A \(32\)
- B \(33\)
- C \(34\)
- D \(35\)
Answer & Solution
Correct Answer
(D) \(35\)
Step-by-step Solution
Detailed explanation
\(\mathrm{m}_1 \mathrm{~m}_2=-1\) so right angle equation circle is \(\begin{aligned} & (x-4)(x-0)+(y-6)(y-0)=0 \\ & x^2+y^2-4 x-6 y=0 \end{aligned}\) \((\mathrm{k}, 3 \mathrm{k})\) lies on it so…
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