ExamBro
ExamBro
JEE Mains · Maths · STD 12 - 6. Application of derivatives

The function \(f(x)=\frac{x}{x^2-6 x-16}, x \in \mathbb{R}-\{-2,8\}\)

  1. A  decreases in \((-2,8)\) and increases in \((-\infty,-2) \cup(8, \infty)\)
  2. B  decreases in \((-\infty,-2) \cup(-2,8) \cup(8, \infty)\)
  3. C  decreases in \((-\infty,-2)\) and increases in \((8, \infty)\)
  4. D increases in \((-\infty,-2) \cup(-2,8) \cup(8, \infty)\)
Verified Solution

Answer & Solution

Correct Answer

(B)  decreases in \((-\infty,-2) \cup(-2,8) \cup(8, \infty)\)

Step-by-step Solution

Detailed explanation

\(f(x)=\frac{x}{x^2-6 x-16}\) Now, \( \mathrm{f}^{\prime}(\mathrm{x})=\frac{-\left(\mathrm{x}^2+16\right)}{\left(\mathrm{x}^2-6 \mathrm{x}-16\right)^2} \) \( \mathrm{f}^{\prime}(\mathrm{x})<0\) Thus \(\mathrm{f}(\mathrm{x})\) is decreasing in…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app